Saturday, September 12, 2009

Divide 16-bit number with 8-bit number using shifting technique(8085)


Statement:Divide the 16-bit unsigned number in memory locations 2200H and 2201H (most significant bits in 2201H) by the B-bit unsigned number in memory location 2300H store the quotient in memory location 2400H and remainder in 2401H.


Assumption: The most significant bits of both the divisor and dividend are zero.
Source program
MVI E, 00 : Quotient = 0
LHLD 2200H : Get dividend
LDA 2300 : Get divisor
MOV B, A : Store divisor
MVI C, 08 : Count = 8
NEXT: DAD H : Dividend = Dividend x 2
MOV A, E
RLC
MOV E, A : Quotient = Quotient x 2
MOV A, H
SUB B : Is most significant byte of Dividend > divisor
JC SKIP : No, go to Next step
MOV H, A : Yes, subtract divisor
INR E : and Quotient = Quotient + 1
SKIP:DCR C : Count = Count - 1
JNZ NEXT : Is count =0 repeat
MOV A, E
STA 2401H : Store Quotient
Mov A, H
STA 2410H : Store remainder
HLT : End of program.

1 comment:

  1. THE ANSWER IF THE DIVIDEND IS FFFF AND THE DIVISOR IS 01 IS WRONG

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